In { \defineBarLine bartype #'(end begin span) }
when `span' is `#f', only the first character of `bartype' is used.
Here is an example:
-----
\version "2.24.0"
{
\defineBarLine ";|" #'(#t #t #f)
a'1 \bar ";|" b'1 \bar
}
-----
This produces a single dotted barline, rather than a dotted-solid
combination as expected.
The explanation is in the definition of bar-line::compound-bar-line on
line 710 of bar-line.scm (the version in 2.24.0, though the current
version in git repository has the same feature). In the initializations:
(let* ...
(span-glyph (get-span-glyph bar-glyph))
(span-glyph-list (string->string-list span-glyph))
when span-glyph is #f, string->string-list returns '(""), a list of
length one. Then further down, the for-each loops over the pair
bar-glyph-list span-glyph-list
and so does just one pass.
A reasonable fix seems to be to add these two lines to the definition of
get-span-glyph, right before the existing "if" statement (line 59 in
version 2.24.0):
(if (and (boolean? span-glyph) (not span-glyph))
(set! span-glyph ""))
[Maybe there's a better way to test if span-glyph is #f --- my knowledge
of scheme is pretty rudimentary!]
Then when span is #f, get-span-glyph will return a list of spaces of
length equal to the length of bar-glyph, which will do the right thing.
This doesn't have any effect on span-bar::compound-bar-line, which does
not use get-span-glyph, but calls
(assoc-get bar-glyph span-bar-glyph-alist)
directly.
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