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RE: GPL Interpretation on load [Was: [bug #61594] suggest new $(hash ...


From: rsbecker
Subject: RE: GPL Interpretation on load [Was: [bug #61594] suggest new $(hash ...) function]
Date: Wed, 1 Dec 2021 09:33:22 -0500

On December 1, 2021 9:25 AM, Eli Zaretskii wrote:
> > From: <rsbecker@nexbridge.com>
> > Date: Wed, 1 Dec 2021 09:09:55 -0500
> > Cc: bug-make@gnu.org, boris@kolpackov.net
> >
> > On December 1, 2021 9:06 AM, Tim Murphy wrote:
> >
> > <big snip>
> > > -load $(XTRA_OUTPUTDIR)/hash$(XTRA_EXT)
> >
> > This thread brings up a question. The load function checks for GPL
> compatibility.
> >
> >       /* Assert that the GPL license symbol is defined.  */
> >       symp = (load_func_t) dlsym (dlp, "plugin_is_GPL_compatible");
> >       if (! symp)
> >         OS (fatal, flocp,
> >              _("Loaded object %s is not declared to be GPL compatible"),
> >              ldname);
> >
> > I am wondering why that is the case. A DLL that is loaded by GNU Make is
> not necessarily subject to GPLv2 or GPLv3. GPLvx makes it clear that you
are
> subject to GPLvx if you include portions of the code from the project
under
> license. However, an external DLL that is loaded by GNU Make via dlopen
> does not have to use any code from the code base. Using a published API,
> which would be the function interface has precedent for being excluded
> from license enforcement - the UNIX kernel API is an example that is
purely
> public domain itself, while the individual header files are subject to
licenses.
> 
> The test doesn't check that the library is under GPL, it tests that it's
"GPL-
> compatible", which means it's Free Software.  GNU Make doesn't want to
> load non-free modules.

That is understood. Is this an official GNU Make policy because it is not
specified that way in GPL. Has the GNU Make team modified their copy of the
GPL license because it is not indicated as a modified version?




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