Re: Backquote simplification

[Hans Aberg]

[Your reply does not seem to be on the list, so I cc it.]

Thanks. I might try an iterated cons, that is a function f such such  
that
  (f x1 ... xk y) --> (cons x1 ... (cons xk y) ...))

Then
  (lambda (x1 ... xk . y) (f x1 ... xk y))
should just return at least k arguments as a list.

I'm not sure right now how to write it, so thankful for help.



On 9 Dec 2010, at 18:44, address@hidden wrote:

> Hi,
>
> You need not use quoting at all in these cases.
>
> ( 1 2 . ( 3 4 ) ) is exactly equivalent to ( 1 2 3 4 ) and ( 1 .  
> ( 2 . ( 3 . ( 4 ) ) ) )
>
> (b ( cons x y ))
> or
> (apply b x y)
>
> I cannot quite tell fom your example.
>
> Cheers,
>  Dan