Re: how to access c-array member in c-structure?

[Taylan Ulrich Bayırlı/Kammer]

<address@hidden> writes:

> On Wed, Mar 30, 2016 at 10:03:28AM +0200, Taylan Ulrich Bayırlı/Kammer wrote:
>> Park SungMin <address@hidden> writes:
>> 
>> > (let ((c-type (list int int (make-list 20000 int))))
>> >     (parse-c-struct
>> >      ((pointer->procedure
>> >        c-type
>> >        (dynamic-func "make_foo" libfoo)
>> >        (list int int))
>> >       4 11)
>> >      c-type))
>> >
>> > also run well…but seems less effective.(if more bigger size…2000000??) 
>> 
>> You could create the type object once at program startup and use it
>> many times.
>> 
>>     (define foo-type
>>       (list int int (make-list 2000000 int)))
>
> If I understood Park SungMin right, the problem is rather with the
> representation of a huge array as a list?

Oh I see.

For me, the following works:

    (define type (list int (make-list 10 int)))

    (define struct (make-c-struct type (list 42 (make-list 10 42))))

    (parse-c-struct struct (list int '*))
      => (1 #<pointer 0x200000002>) 

Is it different when the struct really comes from the C library?

Taylan