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Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ?
From: |
Rhys Ulerich |
Subject: |
Re: [Help-gsl] Target machine defined by gsl-1.15 ? Or by gcc ? |
Date: |
Mon, 24 Sep 2012 11:34:14 -0500 |
Hi Richard,
> I did a build of gsl-1.15 using gcc.exe (tdm64-1) 4.6.1 under MSYS, and I
> used the following command line for configure:
> ./configure CFLAGS="-g -O2 -march=native -fexceptions"
> --prefix=/c/gsl-1.15_64_-g_O2 &> gsl-1.15_configure.out
> ...
> ...the config.log has the following line in the "Platform" section display:
> uname -m = i686
I would have expected something different from 'uname -m'. But I know
nothing about MSYS.
Do the compilation messages echoed by 'make' omit the -march=native
flag you supplied?
If not, can you compile a small test binary with -march=nature and -S
that should contain, say, SSE instructions and observe them in the
output assembly.
If so, then I'd dig into the reason behind the weird 'uname -m' output.
- Rhys