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Re: Variable expansion question
From: |
Sébastien Hinderer |
Subject: |
Re: Variable expansion question |
Date: |
Thu, 27 Oct 2022 14:18:39 +0200 |
Thanks a lot and again, Paul, for your response.
With some help I managed to make the macro work even when the variables
it uses are defined after the call to the macro.
However, I noticed that secondary expansion seem to not play very well
with the shorthand syntax for substitution: $$(foo:=.o) didnr't work,
whereas $$(patsubst %,%.o, $$foo) works. Is this known / documented? Or
did I perhaps miss something and there is a way to make the shorter
syntax work?
Cheers,
Sébastien.