Re: libtool .. [path to shared library] ...

[Gary V. Vaughan]

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Albert Chin wrote:
| Repost as the first try didn't garner a response.
|
| If I invoke libtool as so:
|   $ libtool ... [path to shared library] ...
| is libtool suppose to pass [path to shared library] to the final link
| stage? It's ignoring anything on the command line that ends with
| *$shrext.

I can see no reason why it should.  Passing `-L[path] -l[basename]' will
happily pick up a system .so library even if there is no associated .la file.
~ A quick scan through ltmain.in doesn't reveal any code to deliberately ignore
absolute library paths as far as I can see.  Looks like a bug to me :-(

What exactly are you linking?

Cheers,
        Gary.
- --
Gary V. Vaughan      ())_.  address@hidden,gnu.org}
Research Scientist   ( '/   http://www.oranda.demon.co.uk
GNU Hacker           / )=   http://www.gnu.org/software/libtool
Technical Author   `(_~)_   http://sources.redhat.com/autobook
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