Re: Where is the maplist built-in predicate ?

[spam . spam . spam . spam]

Ok tank you.
So, is there a way to use this usefull library into GNU Prolog?

Selon Paulo Moura <address@hidden>:

>
> On 2010/06/09, at 18:00, address@hidden wrote:
>
> > maplist/2 is a built-in predicate in SWI Prolog.
>
> Wrong, is a library predicate:
>
> $ swipl
> ...
> For help, use ?- help(Topic). or ?- apropos(Word).
>
> ?- predicate_property(maplist(_,_), P).
> P = interpreted ;
> P = imported_from(apply) ;
> P = transparent ;
> P = (meta_predicate maplist(1, ?)) ;
> P = file('/opt/local/lib/swipl-5.11.1/library/apply.pl') ;
> P = line_count(157) ;
> P = number_of_clauses(1) ;
> false.
>
> > I try this :
> >
> > %maplist(?P, ?L) : Apply the predicate P on each element in L
> > maplist(P, []).
> > maplist(P, [X|Xn]) :- call(P, X),maplist(P, Xn).
> >
> > But I get this :
> > | ?- maplist(odd, [z]).
> > no
>
> Shouldn't the query be:
>
> | ?- maplist(odd, [s(z)]).
>
> Cheers,
>
> Paulo
>
>
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