"IFS=: for foo in $FOO:bar:baz; do" doesn't work properly

[Jonathan Kamens]

Configuration Information [Automatically generated, do not change]:
Machine: i386
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i386' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i386-redhat-linux-gnu' 
-DCONF_VENDOR='redhat' -DSHELL -DHAVE_CONFIG_H  -D_GNU_SOURCE 
-D_FILE_OFFSET_BITS=64  -I.  -I. -I./include -I./lib -I/usr/include -O2 
-march=i386 -mcpu=i686
uname output: Linux jik.kamens.brookline.ma.us 2.2.19 #5 SMP Thu Aug 23 
07:00:30 EDT 2001 i686 unknown
Machine Type: i386-redhat-linux-gnu

Bash Version: 2.05
Patch Level: 8
Release Status: release

Description:
        Run this script in bash 2.05:

          #!/bin/sh

          FOO="foo:bar:baz"
          IFS=:

          for ac_dir in $FOO:screlt:freeble; do
              echo $ac_dir
          done

          echo ''

          ac_dummy=$FOO:screlt:freeble
          for ac_dir in $ac_dummy; do
              echo $ac_dir
          done

        You'll see this output:

          foo
          bar
          baz screlt freeble

          foo
          bar
          baz
          screlt
          freeble

        That's wrong.  The first and second blocks of output should be
        identical.

        ash 0.3.7 gets this wrong in the same way.  Bash 1.14.7 gets
        it right.       

Repeat-By:
        See above.

Fix:
        No clue.