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One cant insert a single quote into a variable with built-in substitutio
From: |
Damien Nadé |
Subject: |
One cant insert a single quote into a variable with built-in substitution. |
Date: |
Thu, 31 Jul 2008 16:31:55 +0200 |
Hello
I've tried to insert a single quote into a variable content.
With something like this :
bash-3.2$ foo=bar
bash-3.2$ echo "${foo/%/'}"
>
If you look at that, you understand that > is the $PS2, so it means that
bash is interpreting the single quote a special char.
So, naturally, I've told myself : "just escape it". And I've tried
that :
bash-3.2$ foo=bar
bash-3.2$ echo "${foo/%/\'}"
bar\'
But... what the hell ? The backslash belongs to the variable now ?
So, I cant use it "as is", and if I escape it, the command doesnt do
what I want anymore..
Is that some kind of bug in the parser ?
I've tested that on my fedora 9, with a brand new :
GNU bash, version 3.2.33(1)-release (x86_64-redhat-linux-gnu)
But the same behaviour happens on an old old debian sarge with
GNU bash, version 2.05b.0(1)-release (x86_64-pc-linux-gnu)
D
--
Damien Nadé <anvil@livna.org>
Tel : +33 (0) 4 93 16 88 24
GPG Key ID : 8E279021
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