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Re: different exit codes in $? and address@hidden


From: Chet Ramey
Subject: Re: different exit codes in $? and address@hidden
Date: Fri, 12 Oct 2012 17:04:45 -0400
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv:15.0) Gecko/20120907 Thunderbird/15.0.1

On 10/10/12 10:38 AM, Wladimir Sidorenko wrote:
> Dear all,
> 
> After running the following command:
> 
> $  ! test 0 -eq 0
> 
> I can see different exit codes in $? and address@hidden Here, what I get
> 
> $ ! test 1 -eq 0 ; echo $? address@hidden
> 0 1
> 
> $ ! test 0 -eq 0 ; echo $? address@hidden
> 1 0
> 
> I'd like to know whether that's a desired behavior or a bug.

The current behavior is the intended behavior.  PIPESTATUS reflects the
"true" return status(es) of the process(es) in the pipeline, before any
inversion of the pipeline's exit status.  That's what seems the most
useful.

Chet

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/



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