Re: `printf -v foo ""` does not set foo=

[Chet Ramey]

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On 6/24/13 6:52 PM, Mike Frysinger wrote:
> On Monday 24 June 2013 16:13:01 Chet Ramey wrote:
>> On 6/17/13 1:27 AM, Mike Frysinger wrote:
>>> simple test code:
>>>     unset foo
>>>     printf -v foo ""
>>>     echo ${foo+set}
>>>
>>> that does not display "set".  seems to have been this way since the
>>> feature was added in bash-3.1.
>>
>> printf returns immediately if the format string is null.  It has always
>> been implemented this way.
> 
> seems like when the -v arg is in use, that [otherwise reasonable] shortcut 
> should be not taken ?

Maybe.  I'll take a look.  I suspect that the amount of code that depends
on the current behavior is pretty small.

Chet
- -- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/
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