Re: ${1+"$@"} does not generate multiple words if IFS is empty

[Andreas Schwab]

martijn@inlv.org writes:

>       The substitution ${1+"$@"} should resolve to "$@" if there is at
>       least one parameter -- i.e. one word per parameter. This works fine
>       if IFS contains any character or is unset. If IFS is empty, it
>       instead resolves to the equivalent of "$*", i.e. a single word
>       concatenating all the parameters without a separator. IFS should
>       not influence the behaviour of "$@" under any circumstances.

http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_06_05

"If the value of IFS is null, no field splitting shall be performed."

Andreas.

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Andreas Schwab, schwab@linux-m68k.org
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