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[Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined
From: |
i at maskray dot me |
Subject: |
[Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined |
Date: |
Tue, 19 Jan 2021 23:36:03 +0000 |
https://sourceware.org/bugzilla/show_bug.cgi?id=27210
--- Comment #2 from Fangrui Song <i at maskray dot me> ---
(In reply to H.J. Lu from comment #1)
> (In reply to Fangrui Song from comment #0)
> > cat > a.s <<eof
> > .globl foo
> > .symver foo, foo@v1
> > foo: nop
> > eof
> > echo 'v1 {};' > a.ver
> > cat > b.s <<eof
> > .globl foo_v1
> > foo_v1: nop
> > .symver foo_v1, foo@v1
> > eof
> >
> > exit
> >
> >
> > GNU ld has a special rule removing foo if foo@v1 is defined. gold and LLD
>
> This is done on purpose. A single '@' defines a 'hidden' versioned symbol,
> which is intended for dynamic linker and shouldn't be used by ld to satisfy
> the unversioned reference. ld behavior is correct.
I disagree. This interpretation does not explain why foo_v1 is not suppressed.
The special rule for foo should just be dropped.
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- [Bug ld/27210] New: ld: Don't suppress foo if foo@v1 is defined, i at maskray dot me, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, hjl.tools at gmail dot com, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined,
i at maskray dot me <=
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, i at maskray dot me, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, amodra at gmail dot com, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, i at maskray dot me, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, hjl.tools at gmail dot com, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, i at maskray dot me, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, i at maskray dot me, 2021/01/19
- [Bug ld/27210] ld: Don't suppress foo if foo@v1 is defined, hjl.tools at gmail dot com, 2021/01/20