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Re: [Discuss-gnuradio] Scheduler Help/Question


From: Earle Frank
Subject: Re: [Discuss-gnuradio] Scheduler Help/Question
Date: Wed, 31 Dec 2008 12:32:45 -0800 (PST)

Okay I am using the default scheduler. So now I have enabled the logging for
the appropriate thread-per-block scheduler files.

Here's the heart of my problem. My flow graph has five blocks, A, B, C, D,
E.
Output of A is input to B and C.
Output of C is input to D.
Output of B and D are input to E.

Block A is a file source.

Block B has a 1-to-1 input to output function.

Block C breaks the samples from A into partitions of N samples. The block
does its function over the N samples. Then it outputs the resulting N
values.

Block D looks at the input and produces an enable signal.  The curious
feature, due to implementation, is that this block will only output the
enable signal high once it detects the enable going back low.

Block E takes the inputs from B and D and only outputs the values of B when
D (the enable) is high.

Running this flow graph hangs. Looking at the log files produced for each
block I see that blocks A & B are BLKD_OUT and blocks C, D & E are BLKD_IN.

In this scenario, an enable signal will exist over a partition boundary, say
starts at N-10 and ends at N+10.

At the point of hanging:
Block A has produced N values.
Block B has consumed N values and produced N values.
Block C has consumed N values and produced N values.
Block D has consumed N values and produced N-10 values.
Block E has consumed N-10 values.

If only block A would produce the next N values the system would chug along.
To those smarter than I, is there anything obvious as to why this is
stalling the flow graph?
How does the buffers work in this case?
Block C's input buffer is empty and ready.
Block B has 10 values left in it's output buffer, but shouldn't it be able
to produce more outputs?


Thanks again in advance,
EF

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