> The idea of the u8 data type is that it does a raw dump of the data. So
> if you receive it, then cast the buffer as uint32_t *, you'll get your data.
OK, I thought I was on the same page until this statement.
So I make my output in my verilog code will be 32b, and I can set things up
like normal in the CHDR code. Then my XML files will have "byte" (I saw that
used somewhere, but I see you called it u8, so I will dothat) as the type so
that it will do a raw dump. Then on my receiver side, I set it up to receive a
byte, but I typecast it as uint32_t * to get all 32b back out?
Am I understanding that right?
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