Re: [Fab-user] Set permanent debug output?

[Marco Rogers]

Actually I found the output dict is in fabric.state.  But that works like a charm.  Thanks.

On Mon, Dec 7, 2009 at 5:50 PM, Christian Vest Hansen <address@hidden> wrote:

You can map the "debug" key on the fabric.api.output dict to True,
like in this example:

from fabric.api import local, output
output['debug'] = True

def go():
 local("echo hi", capture=False)

And you can also use the --show=debug command-line argument.

I don't think you can control this from .fabricrc, but I could be wrong.

On Mon, Dec 7, 2009 at 10:04 PM, Marco Rogers <address@hidden> wrote:
> I'm recently getting familiar with context managers in python.  I'd like to
> be able to set the debug output option globally for my fabfile script
> instead of doing "with show('debug'):" in every task.  Ideally I could set
> it in the .fabricrc, but if I can update the global context at the top of
> the script that'd be just as well.  Are either of these currently possible
> and if so, what's the syntax?
> Sorry if I missed this in the docs, but I went over them pretty thoroughly
> and it doesn't seem to address this particular task.
> Thanks, really liking fabric
> :Marco
>
> --
> Marco Rogers
> address@hidden
>
> Life is ten percent what happens to you and ninety percent how you respond
> to it.
> - Lou Holtz
>

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--
Venlig hilsen / Kind regards,
Christian Vest Hansen.

-- 
Marco Rogers
address@hidden

Life is ten percent what happens to you and ninety percent how you respond to it.
- Lou Holtz