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Printing with and without newlines


From: irenezerafa
Subject: Printing with and without newlines
Date: Sat, 13 Nov 2021 21:20:58 +0000

‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐

On Saturday, November 13th, 2021 at 5:35 PM, Dennis Williamson 
<dennistwilliamson@gmail.com> wrote:

> On Sat, Nov 13, 2021 at 11:11 AM irenezerafa via help-bash@gnu.org wrote:
>
> > I would like to have an option on whether to print function arguments with
> > a newline or keep them on the same line.
> >
> > Currently I am using tho following, but is there a more straightforward
> > way to do this?
> >
> > This starts printing from argument nl+1 onwards.
> >
> > case $nwline in
> > 1.  printf '%s\n' "${@:nl+1}" ;;
> >     *) printf '%s' "${@:nl+1}" ;;
> >     esac

> line_end=$'\n'
> printf '%s%s' foo "$line_end" # outputs "foo" followed by a newline

> line_end=''
> printf '%s%s' foo "$line_end" # outputs "foo" without a newline

> Other line endings could be assigned, for example ' ' (space), $'\r' or
> even $'\r\n'.

Dennis, the problem I have is that I cannot use

fs='\n'
printf '%s%s' "${ctp}${@:1:nl}${rst}" "$fs"

Everything remains on the same line.  What can I do?



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