Re: Printing with and without newlines

[Alex fxmbsw7 Ratchev]

nl=$'\n'

notice the $

On Sat, Nov 13, 2021, 22:21 irenezerafa <irenezerafa@protonmail.com> wrote:

> ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
>
> On Saturday, November 13th, 2021 at 5:35 PM, Dennis Williamson <
> dennistwilliamson@gmail.com> wrote:
>
> > On Sat, Nov 13, 2021 at 11:11 AM irenezerafa via help-bash@gnu.org
> wrote:
> >
> > > I would like to have an option on whether to print function arguments
> with
> > > a newline or keep them on the same line.
> > >
> > > Currently I am using tho following, but is there a more straightforward
> > > way to do this?
> > >
> > > This starts printing from argument nl+1 onwards.
> > >
> > > case $nwline in
> > > 1.  printf '%s\n' "${@:nl+1}" ;;
> > >     *) printf '%s' "${@:nl+1}" ;;
> > >     esac
>
> > line_end=$'\n'
> > printf '%s%s' foo "$line_end" # outputs "foo" followed by a newline
>
> > line_end=''
> > printf '%s%s' foo "$line_end" # outputs "foo" without a newline
>
> > Other line endings could be assigned, for example ' ' (space), $'\r' or
> > even $'\r\n'.
>
> Dennis, the problem I have is that I cannot use
>
> fs='\n'
> printf '%s%s' "${ctp}${@:1:nl}${rst}" "$fs"
>
> Everything remains on the same line.  What can I do?
>
>