Re: Bison and $ (dollarsign) token at the end

[Akim Demaille]

| Hello,
| I run bison -v "myfile.y" and got output where last two rules I can't
| understand:
| ----------------------------------------
| state 15
| 
|     $           go to state 16
| 
| 
| 
| state 16
| 
|     $           go to state 17
| 
| 
| 
| state 17
| 
|     $default    accept
| -----------------------------------------
| 
| If parser is in state 15 it needs two $ to accept... huh what $ is for? Is
| it some kind of "end of input"?
| How can I make yylex (flex++) make returns twice (-1)?

Fortunately, no, once is enough.

Still, the presence of these two steps (instead of one) was a bug in
pre 1.30.  Bison 1.35 has one only.

And, yes, as answered by Hans, $ = EOF.

I'm fine with renaming $ to something else.  BYacc names it `$end'.
Avoiding `$eof' is not a bad idea, given that we may be scanning a
string.