Re: Help with shift/reduce conflict

[Hans Aberg]

As Henrik Sorensen points out, you need to be more specific about the 
grammar you want to produce. Here is a suggestion though:

%token YYID
%%
expression:
    hier_id
  | method_call
  | paren_expr
;
paren_expr:
   '(' expression ')'
;
method_call:
    paren_expr '.' YYID paren_expr
;
hier_id :
    YYID
  | hier_id '.' YYID
;


At 12:23 +0200 2005/03/28, Henrik Sorensen wrote:
> On Monday 28 March 2005 00.20, Soumitra Kumar wrote:
> >  1+3.YYID(7) has no meaning. But following is a valid
> >  expression:
> >  (YYID + YYID).YYID().YYID () + YYID() + YYID.YYID() +
> >  YYID.YYID
> for this reduction to make any sense, you need to show more of your grammar.
> What kind of operator is '.' in your grammar ?
>
> Henrik
>
> >  -Soumitra.
> >
> >  --- Henrik Sorensen <address@hidden> wrote:
> >  > can you tell a bit more about what your grammar
> >  > tries to achieve ?
> >  > from your very brief description, it sounds like you
> >  > can do this:
> >  >   1+3.YYID(7)
> >  > but what would this mean ?
> >  > Henrik
> >  >
> >  > On Sunday 27 March 2005 21.37, Soumitra Kumar wrote:
> >  > > %token YYID
> >  > > %%
> >  > > expression : hier_id
> >  > >
> >  > >         | method_call
> >  > >
> >  > >           /* unary and secondary expression
> >  >
> >  > follows.
> >  >
> >  > > */
> >  > >         ;
> >  > > method_call : expression '.' YYID '(' expression
> >  >
> >  > ')'
> >  >
> >  > >         ;
> >  > > hier_id : YYID
> >  > >
> >  > >         | hier_id '.' YYID
> >  > >
> >  > >         ;
> >  > >
> >  > > How to resolve the shift/reduce conflict? Please
> >  >
> >  > help.
> >  >
> >  > > -Soumitra.
> >  > >
> >  > >
> >  > >
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