Re: %prefix with C++ namespaces

[Sebastian Pipping]

Joel E. Denny wrote:
> > If we start "parsing" namespace names, we will have a million
> > new questions to answer.  What is the output of "::foo",
>
> I figured the namespace name is meant to be relative to the global 
> namespace, so a leading "::" is implicit if not specified.

I'm not sure if this is true. Could it be that without "::"
it's relative to the namespace the call was made from instead
of the global namespace?

I assume so because I had lex() in its own namespace and yylex
defined to "lex" working together before.




Sebastian