Re: %prefix with C++ namespaces

[Vincent Zweije]

Sebastian Pipping wrote:
> Joel E. Denny wrote:
> > I figured the namespace name is meant to be relative to the global 
> > namespace, so a leading "::" is implicit if not specified.
> I'm not sure if this is true. Could it be that without "::"
> it's relative to the namespace the call was made from instead
> of the global namespace?
>
> I assume so because I had lex() in its own namespace and yylex
> defined to "lex" working together before.
That is the case.
The leading part of the name (eg foo in foo::bar::baz) is looked up 
using the usual lookup rules for plain identifers. The search starts in 
the scope where it's used, and in subsequently enclosing namespaces 
counting from the place where it's used, ultimately leading to the 
global namespace if it's not found anywhere else.
When the leading part is found to be a namespace, the next part (bar) is 
looked up in that.
The actual workings of qualified name lookup in C++ are pretty 
complicated, especially when you start considering classes and using 
declarations. Read section 3.4 "Name lookup" [basic.lookup] of the C++ 
standard for details.

Ciao.
Vincent.