Make-ing different build.

[Andrea Riciputi]

Hi,
I posted an email last week, but I've not received any answer. Perhaps 
I wasn't able to explain my problem clearly; I'll try again.

I need to write a makefile that allows me to build from basically the 
same sources two different targets. The first is an application (.exe 
file I mean), the latter is a library (.so module). The rules for both 
the target are nearly the same, only some compiler options change.

My intention was to write something like this:

> .PHONY: foo
>
> foo: app.exe
>
> app.exe: $(fooObjectFiles)
>         $(CCompiler) $(fooCFLAGS) $(fooLDFLAGS) $^ -o $@
>
> %.o: %.c
>         $(CCompiler) $(fooCFLAGS) -c $^ -o $@
>
> .PHONY: bar
>
> bar: lib.so
>
> lib.so: $(barObjectFiles)
>        $(CCompiler) $(barCFLAGS) $(barLDFLAGS) $^ -o $@
>
> %.o: %.c
>        $(CCompiler) $(barCFLAGS) -c $^ -o $@

and call make in the following way:

% make foo // When I want to build app.exe

% make bar // When I want to build lib.so

However it doesn't work, because of the double %.o: %.c rule. How can I 
force make to execute the rule related to the target that I want to 
build?

Thanks in advance,
Andrea.

---
Andrea Riciputi

"Science is like sex: sometimes something useful comes out,
  but that is not the reason we are doing it" -- (Richard Feynman)