Re: Execute command for each file in list?

[Boris Godin]

Yours:

$(foreach file, $(FILES), $(eval $call( FILE_Template,$(file))))

Needed:

$(foreach file, $(FILES), $(eval $(call FILE_Template,$(file))))

Cheers

PlebianX wrote:

Nope. Tab doesn't help at all. Can anyone confirm wether or not the script
fragment generated by foreach is placed where the directive was in the
original file? I can imagine that if it's just appended to the end of the
file that this potentially wouldn't work...



Boris Godin wrote:
  

Missing tab?

define FILE_Template
(tab here)$(COMPILER) $(FLAGS) $(1)
endef

Cheers


PlebianX wrote:
    

I'd like to run a command for each file in a list. I feel that the
following
SHOULD work, but appearantly I don't understand how foreach works or
something, because nothing is done (the code is paraphrase for clarity).

FILES = file1.asm file2.asm file3.asm
COMPILER = path/to/compiler
FLAGS = -mp -o2 -k -m -i/lib

define FILE_Template
$(COMPILER) $(FLAGS) $(1)
endef

all:
    $(foreach file, $(FILES), $(eval $call( FILE_Template,$(file))))

What's happening here that I'm missing? Thanks in advance!
  
      

-- 
Boris Godin
*Java Developer* - Gameloft COR
Paraná 560, Nueva Córdoba (CP 5000)
Tel.: (+54 0351) 460 26 26 int. 111
MSN: address@hidden <mailto:address@hidden>

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--
Boris Godin
Java Developer - Gameloft COR
Paraná 560, Nueva Córdoba (CP 5000)
Tel.: (+54 0351) 460 26 26 int. 111
MSN: address@hidden

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