Re: Broken beams' slopes

[David Kastrup]

Carl Sorensen <address@hidden> writes:

> On 8/27/11 7:21 AM, "David Kastrup" <address@hidden> wrote:
>
>> Janek Warchoł <address@hidden> writes:
>> 
>>> I wonder if this solution would yield good results: keep beam slope
>>> before and after break identical (except for some beam quanting,
>>> perhaps, but that's less than 0.3 ss), but modify stem lengths: make
>>> them as long as they would be if there were no beam on the other side
>>> of the break.
>> 
>> I would expect this to yield mostly reasonably results.  I'd also keep
>> beam orientation.  But it might make sense to dole out a bit of spring
>> force (just decidedly less than infinite) for making the vertical beam
>> positions at the break match.
>
>
> It would seem that this algorithm would fail for  a simple broken beam
>
> a8[ b \break c f]

Care to elaborate?

> Or am I missing something?

No idea.

-- 
David Kastrup