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Re: problem with 12/16 beaming


From: Hans Aberg
Subject: Re: problem with 12/16 beaming
Date: Mon, 3 Dec 2007 19:34:15 +0100

On 3 Dec 2007, at 16:58, Trevor Daniels wrote:

Maybe not much help if you have many of these,

You are right: this is a problem. The meter 12/16 is just one possible description of it. If one accepts that, there will be always quadruplet patterns on the 3s in the decomposition 12 = 3+2+2+3+2, with a subaccent (of sort) in the middle of these quadruplets. And from sources as different as Hindemith, "Elementary training", and some Bulgarian sheet music, one can bring out the subaccenting through such subbeaming.

but you
can effect the sub-beaming manually, like this:

\relative c
{
\clef bass
\time 12/16
   \set beatGrouping = #'(3 2 2 3 2)
   \set subdivideBeams = ##t
   #(override-auto-beam-setting '(end * * 12 16) 3 16)
   #(override-auto-beam-setting '(end * * 12 16) 7 16)
   #(override-auto-beam-setting '(end * * 12 16) 10 16)
   \times 3/4 {
     c16
     \set stemRightBeamCount = #1 b
     \set stemLeftBeamCount = #1 c
     c
   }
   d c d g, \times 3/4 {a b c c} d e |
}

So though this looks right, if it can't be automated it would not practically possible.

Alternatively, by changing the time to 24/32 you can
specify beam breaks on 32nd notes, which maybe gives
you what you want for the quadruplets.  You'd then
have to manually change the printed time signature
back to 12/16 - ways of doing this are explained in
the sections on complex meters.  I've not done that
in this example, though:

\relative c {
  \clef bass
  \time 24/32
  \set beatGrouping = #'(3 3 4 4 3 3 4)
  \set subdivideBeams = ##t
  #(override-auto-beam-setting '(end * * 24 32) 3 16)
  #(override-auto-beam-setting '(end * * 24 32) 7 16)
  #(override-auto-beam-setting '(end * * 24 32) 10 16)
  \times 3/4 { c16 b c c } d c d g, \times 3/4 {a b c c} d e
|
}

So this might be better from the practical point of view, though intuitively wrong.

  Hans Aberg






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