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Re: How to split autobeam
From: |
Gilles Sadowski |
Subject: |
Re: How to split autobeam |
Date: |
Mon, 15 Sep 2008 20:45:12 +0200 |
User-agent: |
Mutt/1.5.13 (2006-08-11) |
Hi.
> Here's one example that produces the wrong beaming:
>
> right = \context Voice = "discant"
>
> {
>
> \clef violin
>
> \time 4/4
>
> \relative b' { <<b8. d fis b>> <<bes,16 d f bes>> <<b,8 d fis b>> <<b,8 d
> fis b>>
>
> <<cis,8 eis gis cis>> <<cis,8 eis gis cis>> <<d,8 f a d>> <<d,8 f a d>> }|
>
> }
Hmm, this is still not a complete code: The \score part is missing.
Why do you use the << ... >> construct? A chord is created with something
like
<c e g>4
I.e. with single brackets. Also, the duration is specified after the closing
bracket.
> The compiler produces the correct beaming between the b8. and bes,16 chord
> and between the two b,8 chords.
>
> With the default auto-beam setting the next 4 chords are beamed together. In
> this case the cis,8 chords should
>
> Be beamed together and the two d,8 chords should be beamed.
You didn't tell why the solution I proposed does not satisfy your needs.
Similarly to my previous post, your code above can turned into:
%---
right = \context Voice = "discant"{
\clef violin
\time 4/4
\relative b' {
<b d fis b>8. <bes d f bes>16 <b d fis b>8 <b, d fis b>8
<cis eis gis cis>8[ <cis eis gis cis>8] <d f a d>8[ <d f a d>8] |
}
}
\score {
\right
}
%---
See attached pdf.
> I've tried severla options, for example adding \nobeam to the first d,8
> chord. As a result the last two chords are
>
> Beamed together, but the first two chords (cis,8) are then separated, not
> beamed.
I agree that this behaviour looks strange. Maybe someone else can give an
explanation or confirm that this is a bug.
> Also tried overriding the default auto-beam, but that didnot produce the
> correct result (yet).
In this, I guess that the default behaviour should be what you expect,
without resorting to this.
> Hope you can help or point me in the direction where to look for a solution.
Again, what's wrong with using square (beaming) brackets?
Something like
a8[ b] c[ d]
produces the right result.
Gilles
test2.pdf
Description: Adobe PDF document