Re: When will a #(define ) be executed

[Paul Morris]

Paul Morris wrote
> I think part of the problem is you haven't actually defined
> keepOriginalBreaks as a function/procedure, but just assigned it a value.

Here's something else that might help clarify why it's not working as you
expected it to:

\version "2.18.2"

origBreak = {}

% LilyPond's "define-music-function" returns a procedure
% here it is assigned to origBreak by Scheme's "define"

#(define origBreak
   (define-music-function (parser location)()
     #{ \break #}))

#(display origBreak) #(newline)
% -> #<Music function #<procedure #f (parser location)>>


% but Scheme's "define" does not return anything, so if you try this:

#(define keepOriginalBreaks (define something 10))

#(display keepOriginalBreaks) #(newline)
% -> #<unspecified>

#(display something) #(newline)
% -> 10


There would be less room for confusion if "define-music-function" (and its
friends) were named something like "make-music-function" instead.

Cheers,
-Paul




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