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Re: changing the length (height? positions? endpoints?) of an arpeggio
From: |
Thomas Morley |
Subject: |
Re: changing the length (height? positions? endpoints?) of an arpeggio |
Date: |
Sat, 8 Sep 2018 22:26:54 +0200 |
2018-09-08 22:15 GMT+02:00 Kieren MacMillan <address@hidden>:
> Hi Joram,
>
>> you can set the positions by hand (in staff spaces):
>
> Well, I had tried that in my real-world (non-MWE) example… but it didn’t seem
> to work:
>
> \version "2.19.80"
>
> upper = {
> \time 3/4
> <c'>2.\arpeggio
> \once \override Staff.Arpeggio.positions = #'(3 . -12)
> <c'>2.\arpeggio
> \once \override Score.Arpeggio.positions = #'(3 . -12)
> <c'>2.\arpeggio
> }
>
> lower = {
> \time 3/4
> \clef bass
> <c e g>2.\arpeggio
> <c e g>2.\arpeggio
> <c e g>2.\arpeggio
> }
>
> \score {
> \new PianoStaff <<
> \new Staff \upper
> \new Staff \lower
> >>
> \layout {
> \context {
> \PianoStaff
Because of:
connectArpeggios = ##t
> }
> }
> }
>
> Any thoughts about that?
>
> Thanks!
> Kieren.
You need to go for
\once \override _PianoStaff_.Arpeggio.positions = #'(-3 . 12)
NB the first value of the pair is the lower end!
Thus '(3 . -12) wouldn't print anything.
Or use \offset
\once \offset positions #'(0 . 1) PianoStaff.Arpeggio
HTH,
Harm
Re: changing the length (height? positions? endpoints?) of an arpeggio, Torsten Hämmerle, 2018/09/08