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[Octave-bug-tracker] [bug #59616] nested while cant detect parameter cha
From: |
Rik |
Subject: |
[Octave-bug-tracker] [bug #59616] nested while cant detect parameter change |
Date: |
Thu, 3 Dec 2020 20:01:10 -0500 (EST) |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.198 Safari/537.36 |
Update of bug #59616 (project octave):
Status: None => Invalid
Open/Closed: Open => Closed
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Follow-up Comment #1:
The code is working properly. You initialize u to the value of 1 and then
enter the first while loop. In the second while loop you print the value of
u, but do not change it. The value of u (1) is printed 16 x 16 x (176/16) =
2,816 times and then the inner while loop completes.
u is then incremented by 16 and the first while loop starts again. It prints
the value of u (17) and then checks the condition for the innerwhile loop.
Because v has not been changed, it is already larger than 176 from the first
time through the while loop and so it is never executed. The outer while loop
continues incremented u by 16 for each round. The last bits of output on my
screen are
u = 1
u = 1
u = 1
u = 1
u = 1
u = 1
u = 17
u = 33
u = 49
u = 65
u = 81
u = 97
u = 113
u = 129
Octave is correctly interpreting the code you have written so I'm closing this
report.
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<https://savannah.gnu.org/bugs/?59616>
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