Re: how to pass arguments with space inside?

[Chris F.A. Johnson]

On Thu, 9 Apr 2009, lehe wrote:

> Sorry. I won't top post again.

  You just did!

> I tried your way but ARG_OPTS only accept the first argument and ignore the
> rest.

ARG_OPTS=( "$@" )

   All the arguments are now in the array ARG_OPTS:

printf "%s\n" "${ARG_OPTS[@]}"

> Mike Frysinger wrote:
> > On Thursday 09 April 2009 17:47:59 lehe wrote:
> > > Thanks Mike.
> >
> > please do not top post
> >
> > > Mike Frysinger wrote:
> > > > On Thursday 09 April 2009 16:46:27 lehe wrote:
> > > > > I was wondering how to pass arguments with space inside. For example,
> > > my
> > > > > bash script looks like:
> > > > >
> > > > > #!/bin/bash
> > > > > ARG_OPTS=""
> > > > > while [[ -n "$1" ]];
> > > > >         ARG_OPTS="${ARG_OPTS} $1"
> > > > >         shift
> > > > > done
> > > > >
> > > > > If I pass an argument like "--options='-t 0 -v 0'", then it would be
> > > > > splitted by the spaces inside, ie "--options='-t", "0", "-v" and "0".
> > > > >
> > > > > How can I achieve what I wish?
> > > >
> > > > use arrays
> > > >
> > > > $ f=( a "b c" d)
> > > > $ printf '%s\n' "${f[@]}"
> > > > a
> > > > b c
> > > > d
> > >
> > > Could you explain it a little? I don't quite get it. How to apply this to
> > > argument parsing?
> >
> > instead of gathering stuff into the variable ARG_OPTS, declare it as a
> > variable and gather it there:
> > declare -a ARG_OPTS
> > while [[ -n $1 ]] ; do
> >         ARG_OPTS[${#ARG_OPTS[@]}]="$1"
> >         shift
> > done
> >
> > then use it like i showed and the argument grouping will be preserved:
> > "${ARG_OPTS[@]}"
> >
> > i imagine there are plenty of bash array howtos out there if you google
> > -mike
>
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   Chris F.A. Johnson, webmaster         <http://woodbine-gerrard.com>
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