Re: how to pass arguments with space inside?

[Chris F.A. Johnson]

On Fri, 10 Apr 2009, Greg Wooledge wrote:

> On Fri, Apr 10, 2009 at 12:02:56AM -0700, lehe wrote:
> > The reason why I don't use "$@" is that the arguments to the bash script is
> > not completely those for the executable. Some of them are just arguments
> > only to the bash script. So actually the script is like
>
> So you need to build up an *array* of your parameters, not a string.
> What you are trying to do does not, and cannot, work.
>
> > [code]
> > #!/bin/bash
> > ...
> > ${DEBUGGER} my_executable ${ARG_OPTS}
> > [/code]
>
> You have built up a string.  There is no way to delimit individual
> parameters inside a string other than whitespace, and when you need
> whitespace *inside* one of those parameters, you're stuck.  You need
> an array instead, as others have already told you.

   No, it is quite easy without arrays, but not *as* simple. If you
   build the strings with a character that is not in the arguments as
   a delimiter.

   The OP doesn't seem able to grasp either arrays or the meaning of
   top posting.

> [code]
> #!/bin/bash
> ....
> $DEBUGGER my_executable "${MY_ARRAY[@]}"
> [/code]
>
> See also:
>
> http://mywiki.wooledge.org/BashFAQ/050
>
>  "I'm trying to put a command in a variable, but the complex cases
>  always fail!"
>
> http://mywiki.wooledge.org/BashFAQ/005
>
>  "How can I use array variables?"

--
   Chris F.A. Johnson, webmaster         <http://woodbine-gerrard.com>
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   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)