Re: Bug in function return statement in while subshell

[Pierre Gaston]

On Mon, Jul 29, 2013 at 8:15 PM, Roman Rakus <rrakus@redhat.com> wrote:
> On 07/29/2013 05:06 PM, Chet Ramey wrote:
>>
>> On 7/29/13 10:55 AM, Roman Rakus wrote:
>>>
>>> I didn't take a look on where the problem could be, but it is discussed
>>> on
>>> stackoverflow [1].
>>>
>>> Looks like return builtin falsely exit execution of while loop instead of
>>> function.
>>
>>
>> What would you like to see happen?  You're in a subshell: the function
>> can't return, since this is not the shell that called it.  Do you want
>> parent and child shells both continuing execution after the function call?
>>
>> Chet
>>
> As Chris said, some error, because return is not in function.
>
> Example:
> f1() {
>     : | while :; do return 3; done
>     echo $?
>     return 1
> }
> echo $?
> f1; echo $?
> return 2
>
> Looks like the bash doesn't restore the i'm-in-function indicator when
> running compound command (like while or if) in functions' subshell.
>
> RR
>

what about things like this: foo () (  return 1; )

I suspect it's not so uncommon, it's in a subshell, in a function?