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From: | Cory Papenfuss |
Subject: | Re[2]: [Discuss-gnuradio] DC-DC converter |
Date: | Mon, 6 Dec 2004 11:09:09 -0500 (EST) |
My concern would be how the inductors tend to smack the diodes. Once the diode gives in to being smacked around by the inductor, your 4702/4707 is the next target. If you pull/break the diode on many simple charge pump circuits, it simply stops working. If you pull/break the diode on the inductive buck circuit, it tends to create what ever voltage the inductor desires. The inductors are defiantly better for the power output. The charge pump definitely can't touch the 3 amps. Best regards, ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Jared Harvey HAM KB1GTT
You are both right and wrong. A *properly designed* power electronic circuit does not abuse any device except as a second-order effect (requiring snubbers, limiting di/dt and dv/dt, etc). If you do not design it correctly and have "shoot-through" faults (for a voltage-source converger, i.e. capacitor) or "open" faults (for a current-source, i.e. inductor) then you will destroy the devices. A switched capacitor circuit abuses the devices as a *first-order* operating parameter (i.e. connecting capacitors directly across voltage sources/sinks means *huge* current spikes.) A proper power electronics circuit simply passes the "baton" (voltage to inductors and current to capacitors) gracefully.
For the buck circuit you mentioned it's true that if you remove the diode the switch will blow up. That is the "open" fault to be avoided for the current-source converter. If the circuit is properly designed, the diode won't fail.
-Cory ************************************************************************* * Cory Papenfuss * * Electrical Engineering candidate Ph.D. graduate student * * Virginia Polytechnic Institute and State University * *************************************************************************
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