[help-bison]How to stock information?

[soledady]

if you receive for twice time this message i'm sorry i made a mistake

Hello, i'm using Bison for compute a mathematic tool to resolve this
kind of thing: 
u(n)=u(n-1)+3*u(n-2);u{0}=1;u{1}=2;
 the example is very simple and this tools can do more things 
So the subject:
 when I execute bison It builds a syntaxical tree (doesn't it?)
 how recover number (they could change of course) in a correct order
cause i need to know how the formulation is written..
i give you a parse of the code: (the print are just here in order for me
to understand how does it works)

g       :       '=' d g                 {printf("=");}
                |U '{'N '}' g           {printf("U{N}");}
                |U '{ N '-'NB'}'g       {printf("U{n-%d}",$5);} 
                |U '{' N '+' NB '}' g   {printf("U{N+%d}",$5);}
                |U '{' NB '}' g         {printf("U{%d}",$3);}
                |d g                    {printf(" ");}
                |V g                    {printf(" ");}
                |/*empty*/              {printf(" ")}   
d       :       g T                     {printf(" ");}
                |NB ';'                 {printf(" %d ",$1);}
                
T       :       /*vide*/                {printf("  ");} 
                |NB T                   {printf("%d",$1);}
                |'*' T                  {printf("*");}
                |'/' T                  {printf("/");}
                |'^' T                  {printf("^");}
                |'+' T                  {printf("+");}
                |'-' T                  {printf("-");} 
                |';' T                  {printf(";");}
so for this part of an example (without all the rest of the example)
U{N}=U{N-1}+3*U{N-2}; U{0}=1; U{1}=2;
it's give me:
*3+    ;  1  2   =U{1}=U{0} U{n-2} U{n-1}    =U{N}


how can i do to recover correctly which number for which part of code ?
more precisely i need to generate code in java and to do that i need
which kind of fomulation its given? 

thanks for your help! 

if you need more precision let's continue:
moreover it's inside of a group of result globaly like that

for this code:the indentation are here just to be clearer
begin
         Name=Suite;
        begin
         DEFINITION=RECURRENTE;
         U{N}=U{N-1}+3*U{N-2};
         U{0}=1;
         U{1}=2;
         TERME[1..8];
         VARIATION;
         TYPE; 
        SI_ARITH 
                begin
                 FORMULE_ARITH;
                 SOMME_ARITH[1..8];
                end
        SI_GEO 
                begin
                 FORMULE_GEO;
                 SOMME_GEO[1..8];
                end
        end
end


i'have this tree (the printf("blabla"); ) the indentation are here just
to be clearer

*3+    ;  1  2 
SumAri  formulArith
   begin qa end [1..8]   sumGeo  formulgeo 
 begin qb end   si_Geo  si_arith     type  variation; terme 
  =U{1}=U{0} U{n-2} U{n-1}  =U{N}
recurrente Definition=
 begin  end name=(null)|
begin end
 syntax error


thanks for your help!