Re: execute commands in foreach loop

[Mike Shal]

On 7/23/09, Fritz Code <address@hidden> wrote:
>  I've a problem with the following make foreach construct:
>
>  $(foreach tobuild,$(shell cat file.dist | awk -F/ '{print $$1}'),
>  $(call mymake,$(tobuild))
>
>  define mymake
>     $(MAKE) $1
>  endef
>

It looks like you expect the $(foreach) to actually execute make on
each of the targets? You might just want to put that in the command
script for a default target, like so:

define mymake
   $(MAKE) $1;
endef
all: ; $(foreach tobuild,$(shell cat file.dist | awk -F/ '{print
$$1}'),$(call mymake,$(tobuild)))

target1: ; @echo "Making target1"
target2: ; @echo "Making target2"

I made a file.dist file contain:

target1
target2

Note that in the Makefile, I added a ';' after the $(MAKE) $1 line so
it will run separate commands. Also I added another ')' after the
$(call) function to properly end the $(foreach) function.

Does that do what you want? Why do you want your targets in a separate
file.dist file? It would seem much simpler if you just used make and
did something like:

all: target1 target2
target1: ; @echo "Making target1"
target2: ; @echo "Making target2"

Maybe I'm completely misunderstanding what you're trying to accomplish.

-Mike