Re: Spaces in args, escapes, and command substitution

[bash]

>
>That's because you set IFS for the vi, but not for the command
>substitution.  Break your result into two commands:
>
>IFS='\n'
>vi $(grep -l PATTERN *)
>

So the IFS setting takes effect immediately after it is seen?
So a newline is needed?

I would have hoped that the IFS was interpreted after its delimiter
has been encountered, so that the single line example would work.