Re: [talk] easy tuplets

[Keith OHara]

On Mon, 24 Sep 2012 08:40:50 -0700, Janek Warchoł <address@hidden> wrote:

> I imagine that we could have arbitrary integer durations intended for
> use with straightforward tuplets, while continue using explicit \times
> command for complicated (for example nested) ones.

Try it out.  Enter some Debussy using 12th-notes, 9th notes, etc.
<http://www.mutopiaproject.org/cgibin/make-table.cgi?searchingfor=debussy>

> And by the way, look at the output of this:
>
>   \times 2/3 { b8 }
>   \times 2/3 { b8 }

We sometimes need numbers on each stem, for example tremolos c6.:12

> As for dividing tuplets here
>
> \times 2/3 { c8 c c c c c c c c c c c
>              c8 c c c c c c c c c c c }
>
> we can use tupletSpannerDuration.  We could have it calculated from
> time signature or something like that.

The auto-beaming code beams triplet rhythms correctly, with rare exceptions, 
when they are written out
  { c8*2/3 c c c c c c c c c c c
    c c c c c c c c c c c c }

> > > "the casual atmosphere of a friendly
> > > discussion at a pub or coffee house"
> >
> > Would you be rather thinking of a Scottish or a Canadian pub here?
>
> what's the difference?
Canadians are known for being exceptionally polite.

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