Re: [Gnu-arch-users] Re: MD5 is broken

[Andrew Suffield]

On Wed, Mar 16, 2005 at 11:07:27AM -0800, Tom Lord wrote:
> You argue that while one function will certainly be broken,
> it is unlikely that two functions will be broken at the same 
> time.
> 
> But logically speaking, the combination of two hash functions
> is a single hash function.  It is just as "a priori" likely
> that the combination will be broken.

You can't restate temporal logic in classical predicate logic that way
and come up with a correct conclusion. It is very unlikely that the
combination will be broken *simultaneously*, and a non-simultaneous
break is not a vulerability.

-- 
  .''`.  ** Debian GNU/Linux ** | Andrew Suffield
 : :' :  http://www.debian.org/ |
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